a^3+b(3+c)(4-c)=0

Solution for a^3+b(3+c)(4-c)=0 equation:

Simplifying
a3 + b(3 + c)(4 + -1c) = 0

Multiply (3 + c) * (4 + -1c)
a3 + b(3(4 + -1c) + c(4 + -1c)) = 0
a3 + b((4 * 3 + -1c * 3) + c(4 + -1c)) = 0
a3 + b((12 + -3c) + c(4 + -1c)) = 0
a3 + b(12 + -3c + (4 * c + -1c * c)) = 0
a3 + b(12 + -3c + (4c + -1c2)) = 0

Combine like terms: -3c + 4c = 1c
a3 + b(12 + 1c + -1c2) = 0
a3 + (12 * b + 1c * b + -1c2 * b) = 0
a3 + (12b + 1bc + -1bc2) = 0

Solving
a3 + 12b + 1bc + -1bc2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-12b' to each side of the equation.
a3 + 12b + 1bc + -12b + -1bc2 = 0 + -12b

Reorder the terms:
a3 + 12b + -12b + 1bc + -1bc2 = 0 + -12b

Combine like terms: 12b + -12b = 0
a3 + 0 + 1bc + -1bc2 = 0 + -12b
a3 + 1bc + -1bc2 = 0 + -12b
Remove the zero:
a3 + 1bc + -1bc2 = -12b

Add '-1bc' to each side of the equation.
a3 + 1bc + -1bc + -1bc2 = -12b + -1bc

Combine like terms: 1bc + -1bc = 0
a3 + 0 + -1bc2 = -12b + -1bc
a3 + -1bc2 = -12b + -1bc

Add 'bc2' to each side of the equation.
a3 + -1bc2 + bc2 = -12b + -1bc + bc2

Combine like terms: -1bc2 + bc2 = 0
a3 + 0 = -12b + -1bc + bc2
a3 = -12b + -1bc + bc2

Simplifying
a3 = -12b + -1bc + bc2

Reorder the terms:
a3 + 12b + bc + -1bc2 = -12b + 12b + -1bc + bc + bc2 + -1bc2

Combine like terms: -12b + 12b = 0
a3 + 12b + bc + -1bc2 = 0 + -1bc + bc + bc2 + -1bc2
a3 + 12b + bc + -1bc2 = -1bc + bc + bc2 + -1bc2

Combine like terms: -1bc + bc = 0
a3 + 12b + bc + -1bc2 = 0 + bc2 + -1bc2
a3 + 12b + bc + -1bc2 = bc2 + -1bc2

Combine like terms: bc2 + -1bc2 = 0
a3 + 12b + bc + -1bc2 = 0

The solution to this equation could not be determined.